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Mathematics 20 Online
OpenStudy (askme12345):

let x = the number of people asked (Statistics!)

OpenStudy (kirbykirby):

Euh could you somehow fix this paragraph. It is very confusing to read without Capital letters, and it seems like part of it was typed twice :S

OpenStudy (askme12345):

If that can help you explain it sure lol: Opinion is split on a new proposed law. At a given campus 35% of people support the new proposal. Suppose we want to ask students how they they feel until we met someone in favor. Let x= the number of people asked. a) what type of probability distribution does the random variable x have? (explain) b) What is the probability the second person we ask is the first person we meet in favor of the proposal?

OpenStudy (kirbykirby):

Ok this is much more clear

OpenStudy (kirbykirby):

a) This would be a geometric random variable. You have a discrete distribution. Essentially, you are counting the number of failures until the first success That is, you are counting the number of people who are not in favour (failures) until you meet the first success (someone in favour)

OpenStudy (askme12345):

oh okay makes sense

OpenStudy (kirbykirby):

Do you now how to do b) now

OpenStudy (askme12345):

do i use p(k)=(1-alpha)^k-1 alpha

OpenStudy (kirbykirby):

yes

OpenStudy (askme12345):

im not 100% sure how to plug in

OpenStudy (askme12345):

is the percent the alpha? and 2 the k?

OpenStudy (kirbykirby):

yes and yes

OpenStudy (kirbykirby):

With this formula, K = # of total trials. So you asked 2 people, hence 2 trials. And alpha s the probability of success. Here, 35% is the probability of success (the proportion in favour)

OpenStudy (askme12345):

so (1-.35)^1 (.35) = .2275 Thank you soooo much, im actually getting statistics for once ! Can you help me with the last part to this quesiton: What is the probability we have to ask at most 3 people? Would have have to do the same formula for 1, 2 and 3 and multiply them?

OpenStudy (kirbykirby):

At most 3 people means up to and including 3 people

OpenStudy (kirbykirby):

so you're interested in \(P(K\le 3)\)

OpenStudy (kirbykirby):

\(P(K\le 3)=P(K=1)+P(K=2)+P(K=3)=p(1)+p(2)+p(3)\)

OpenStudy (kirbykirby):

so you plug in the numbers 1, 2, 3 in your formula and add them up basically

OpenStudy (kirbykirby):

Sorry I didn't answer earlier I got busy with something

OpenStudy (kirbykirby):

but yeah stats/probability kind of takes time to get your head around it

OpenStudy (askme12345):

THANK YOU so much!! *****

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