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What is the antiderivative of (4-t)t^(1/2)
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distribute t^(1/2) ?
I get the general idea. I'm trying to look at (4-t) as u and t^(1/2) as v
can I do that when finding the antiderivative?
I guess so since it is equivalent
so, 4t^(1/2) -t^(3/2) ?
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using by parts for this is like using a nuclear bomb to kill a mosquito :/
yup !
lol nice analogy
and take integral of each term thats easy right :)
hmm ok so then
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\( \large \int (4-t)t^{1/2} dt\) \( \large \int 4t^{1/2} - t^{3/2}dt\)
(8/3)t^(3/2) -(2/3)t^(5/2)
first term looks fine, check second term again
ah 2/5
yah :)
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w00t
thanks again as always :)
np :)
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