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Mathematics 17 Online
OpenStudy (anonymous):

What is the antiderivative of (4-t)t^(1/2)

ganeshie8 (ganeshie8):

distribute t^(1/2) ?

OpenStudy (anonymous):

I get the general idea. I'm trying to look at (4-t) as u and t^(1/2) as v

OpenStudy (anonymous):

can I do that when finding the antiderivative?

OpenStudy (anonymous):

I guess so since it is equivalent

OpenStudy (anonymous):

so, 4t^(1/2) -t^(3/2) ?

ganeshie8 (ganeshie8):

using by parts for this is like using a nuclear bomb to kill a mosquito :/

ganeshie8 (ganeshie8):

yup !

OpenStudy (anonymous):

lol nice analogy

ganeshie8 (ganeshie8):

and take integral of each term thats easy right :)

OpenStudy (anonymous):

hmm ok so then

ganeshie8 (ganeshie8):

\( \large \int (4-t)t^{1/2} dt\) \( \large \int 4t^{1/2} - t^{3/2}dt\)

OpenStudy (anonymous):

(8/3)t^(3/2) -(2/3)t^(5/2)

ganeshie8 (ganeshie8):

first term looks fine, check second term again

OpenStudy (anonymous):

ah 2/5

ganeshie8 (ganeshie8):

yah :)

OpenStudy (anonymous):

w00t

OpenStudy (anonymous):

thanks again as always :)

ganeshie8 (ganeshie8):

np :)

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