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Mathematics 15 Online
OpenStudy (anonymous):

Write a polynomial function of the least degree that has real coefficients, the given zeros, and a leading coefficient of 1 (Write your answer in standard form) x=4,2i,-2i

ganeshie8 (ganeshie8):

hint : complex roots come in pairs

ganeshie8 (ganeshie8):

thats a pretty useless hint :/ already you're given pair of zeroes lol

OpenStudy (mathmale):

Indeed. Root 2i corresponds to factor (x-2i); root -2i corresponds to (x+2i). Root 4 corresponds to what factor? What next in the sol'n of this problem? @ganeshie8: You're forgiven (this time only). :)

ganeshie8 (ganeshie8):

:)

OpenStudy (mathmale):

Cool-1: would you please multiply together (x-2i) and (x+2i)? What do you get?

OpenStudy (anonymous):

(x^2+4)?

OpenStudy (anonymous):

so (x-4) (x^2+4)

OpenStudy (anonymous):

= X^3-4x^2+4x-16

OpenStudy (mathmale):

I haven't checked every detail, but it appears that you're doing exactly the right thing. Note that the "leading coefficient" is 1: \[1x^3\]has the coeff. ' 1 ' and thus satisfies that particular requirement.

OpenStudy (mathmale):

Cool, Cool-1! Looks like you're making very good progress.

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