Question

How do I calculate the volume of dry hydrogen which would be produced by 1 mole of Mg at room temperature and 1 atmosphere pressure?

Answer 1

write the equation for the process and use stoichiometry (i.e. molar ratio), then use PV=nRT to find the volume.

Answer 2

Reaction equation : Mg(s) + 2 HCl (aq) -> MgCl2 (aq) + H2 (g)
Amount of Hydrogen is 1 mole
Remember, temperature is 298.15 K and p = 1.01325 bar.