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OpenStudy (anonymous):
How do I calculate the volume of dry hydrogen which would be produced by 1 mole of Mg at room temperature and 1 atmosphere pressure?
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OpenStudy (aaronq):
write the equation for the process and use stoichiometry (i.e. molar ratio), then use PV=nRT to find the volume.
OpenStudy (gebooors):
Reaction equation : Mg(s) + 2 HCl (aq) -> MgCl2 (aq) + H2 (g) Amount of Hydrogen is 1 mole Remember, temperature is 298.15 K and p = 1.01325 bar.
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