F is a cubic polynomial written as f(x)=ax^3+bx^2+cx+d find conditions on a,b,c such as F has (i) two critical points. (ii) one critical point. (iii) no critical points. Using the results from above to solve: (b) If F has only one critical point, then x=?
So you know how to find critical numbers?
All I have is y prime. y=3ax^2+2b+c than use guad formula on that.
And when do you have 2 real solutions ?
When what is bigger than 0?
it starts with a d
discr....
and it is y=3ax^2+2bx+c do you know what d word I'm talking about?
discrimination
discriminant
not discrimination that is what happens when people don't like another group of people
Yea. My bad. sorry.
Im totally lost.
so recall if you have y=ax^2+bx+c two real solutions will happen if b^2-4ac>0 one real solution will happen if b^2-4ac=0 no real solutions will happen if b^2-4ac<0
So find the discriminant for your equation.
Yep. I have that. But i don't know how to find the discriminant for the equation.
\[y=Ax^2+Bx+C\] \[D=B^2-4AC\] Your equation is \[y'=3ax^2+2bx+c\] What is A for our equation?
have no idea
A is the thing in front of x^2 what is the thing in front of your x^2?
3
what about 3a is not that in front of x^2?
Yea. 3a
I didn't think it was important to write the A
look we are comparing these equations: \[y=Ax^2+Bx+C\] \[y=3ax^2+2bx+c\] A=3a <--these were both the things in front of x^2 now what is B=?
2b
ok and course C=c so what is our discriminant D?
d just goes away. i thnk
\[D=B^2-4AC\] what is D with the values we just found for A,B, and C?
no clue
well you told B=2b and A=3a and C=c so you can find D b replacing those values in D
is d=3
is that the answer?
No.
Join our real-time social learning platform and learn together with your friends!