Question

sqrt-72x^5

Answer 1

Hello and Welcome to OpenStudy! :)

what would you like to do with this? :/

Answer 2

I would like some help with some college algebra..

Answer 3

hmmm... I'm not very good at that sort of stuff, sorry
I'll tag some people that could help you though :)
(and sorry about the people in the chat, they can be immature at times)

@math&ing001 @sourwing @whpalmer4 @wio if you're not too busy, could you pwease help?

Answer 4

You don't know how to simplify it?

Answer 5

is that -72?

Answer 6

\[\sqrt{-72x^5}\]

Answer 7

this is the problem I am stuck on. Thanks

Answer 8

well, since you can't take a square root negative number, -72x^5 ≥ 0, that gives x ≤ 0.

With the specified restriction, the expression now can be reduced to
sqrt(72x^5),

can you take it from here?

Answer 9

@jigglypuff314 i'll leave that to you :D

Answer 10

No, that doesn't help...

Answer 11

no @sourwing ! I FAILED Algebra 2 cuz of imaginary numbers >,<

Answer 12

\[
\sqrt{-72} = \sqrt{72}\times \sqrt{-1}
\]

Answer 13

sqrt(-72x^5) is equivalent to sqrt(72x^5), provided that x≤0

sqrt(72x^5) = sqrt(72) sqrt(x^5)
= sqrt(6*6*2) * sqrt(x^2 * x^2 * x)
= 6sqrt(2) x^2 sqrt(|x|)

Answer 14

\[
72= 2^3\times 3^2 = 2\times (2\times 3)^2
\]

Answer 15

To be pedantic, that fist statement you made is not quite correct.

Answer 16

are we in real numbers or imaginary? I was thinking the former

Answer 17

I was thinking imaginary... ....
so just square root everything like you would without a negative, then add an "i" somewhere >.>

Answer 18

the question is asking to evaluate the following sqrt expression

Answer 19

yes, do you know how to do just sqrt (72x^5) ?

Answer 20

well the thing is sqrt(-72x^5) isn't necessarily an imaginary number because x can vary. That is the reason I said x≤0

Answer 21

6i√2x^5 ?

Answer 22

6i sqrt(2x^5) ?
if this is the case, you're assuming x ≥ 0 , which is back to the question whether were in real or imaginary

Answer 23

sqrt(-72x^5) is real of x ≤ 0, and imaginary if x > 0. I'm thinking it has to be one or the other.

Answer 24

You can't just do sqrt(-72x^5) = sqrt(-1) sqrt(72x^5) unless you had already specify the restriction for x

Answer 25

the answer was 6x^2isqrt2x

Answer 26

so we're in imaginary then.

Answer 27

okay here is one I keep getting wrong.. lol 2i/3+7i (in fraction form