Question

Consider the following limit
lim 3x/√[(x^2)+3]
x→−∞

a) Use the definition of limits at infinity to find values of N that correspond to ε = 0.5

N =

b) Use the definition of limits at infinity to find values of N that correspond to ε = 0.1

N =

I already found x1 = (ε-3)√[(3)/6ε-ε^2]

Answer 1

are you using cauchy?

Answer 2

no. what's that?

Answer 3

nvm

Answer 4

ok. can you help me with this question?

Answer 5

I know I put 0.5 and 0.1 in for ε but I when I try to solve it from there I get the wrong answer.

Answer 6

i dont know what the e is, but to take that limit as it goes to infinity you can divide everything by \[\sqrt{x ^{2}}\] so you will get 3/√[1+3/x] as it goes to infinity and it gives you 3

Answer 7

\[x _{1}= (\epsilon-3)\frac{ \sqrt{3} }{ 6 \epsilon - \epsilon ^{2}}\]

Answer 8

the e is epsilon

Answer 9

didnt learn this, but you couldnt find any examples in your book? you can go on calcchat if you use their book and try to find an example problem

Answer 10

no it's on webassign

Answer 11

the examples aren't very helpful in the book

Answer 12

I haven't tried CalcChat yet, guess I will now

Answer 13

yea i would find an odd number example in the book thats close to it and find the worked out solution in calcchat. good luck.

Answer 14

just found one and it's the same exact problem I have

Answer 15

nice, so how do you do it? or send me a link to the calcchat problem