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Mathematics 16 Online
OpenStudy (anonymous):

Find the derivative: r(x)=Cot (u(x)) s(x)=U(Cot(x))

OpenStudy (rock_mit182):

i believe you have to apply the chain rule

rvc (rvc):

chain rule

rvc (rvc):

\[cotx (dy/dx \cot x)+\cot x(dy/dx \cot x)\]

rvc (rvc):

@nahal_amani

OpenStudy (gorv):

\[\frac{ d \cot(u(x)) }{ dx }=-cosec^{2}(u(x))*\frac{ du(x) }{ dx }\]

OpenStudy (gorv):

\[\frac{ du(cotx) }{ dx }=u'(cotx)*\frac{ dcotx }{ dx }\]

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