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OpenStudy (anonymous):
how to integrate (dy/dx)=[3(x+y)] /x ?
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OpenStudy (nincompoop):
distributive property
then separate them as terms with denominator x
OpenStudy (anonymous):
=3+(3y/x)???
OpenStudy (nincompoop):
distributive property
OpenStudy (anonymous):
yes, so distribute the 3 and then split up the numerator~?
OpenStudy (nincompoop):
have a rest and do it again when you have a refreshed brain :P
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OpenStudy (anonymous):
? wait wat?
OpenStudy (nincompoop):
distributive property is multiplication yes?
3(x+y) = ?
OpenStudy (anonymous):
3x+3y, but then there is a x on the bottom, so then the x's cancel in the first term, leaving just 3, and the second term is left with 3y/x.
OpenStudy (nincompoop):
1/x * (3x + 3y)
OpenStudy (nincompoop):
okay
then you have
integral (3 + 3xy) dx
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ganeshie8 (ganeshie8):
looks its not separable,
familiar with computing IF and multiplying both sides... ?
OpenStudy (anonymous):
its a homogenous equation try using y=vx
so dy/dx=v+xdv/dx
OpenStudy (nincompoop):
integral (3 + 3x/y) dx
OpenStudy (anonymous):
???????? confusion!!!! its not seperable?
OpenStudy (anonymous):
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