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Simplify the expression. Write the answer without using parentheses or negative exponents (ab^3)^-4
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\[\left( ab^3 \right)^{-4}=\frac{ 1 }{ \left( ab^3 \right)^4 }=?\]
So, what do I need to dothere.
\[\left( x^2y^3 \right)^5=x ^{2*5}y ^{3*5}=x ^{10}y ^{15}\] a has exponent 1,b has exponent 3, can you solve? i have given you an example.
you got it or should i proceed.
\[=\frac{ 1 }{ a^4b ^{3*4} }=\frac{ 1 }{ a^4b ^{12} }\]
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Yeah is that the answer than ?
@surjithayer
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