Question

-4x^2+4x+3>0

Answer 1

foil method

Answer 2

foil? try factoring

Answer 3

6.If –4x2 + 4x + 3 > 0, then which of the following inequalities must be true?
1.x > 0
2.x < 0
3.x < [negative one half] or x > [three halves]
4.[negative one half] < x < [three halves]
5.[negative two thirds] < x < [one half]

It has been so long since I have done this that I do not even know where to start.

Answer 4

factor

Answer 5

i would start by changing it from \[-4x^2+4x+3>0\] to \[4x^2-4x-3<0\] i.e. multiply by \(-1\)
then it is easier to factor it

Answer 6

haha I meant factor lol

Answer 7

when you factor, you get
\[(2x+1)(2x-3)<0\] and now the zeros are easy to find, they are \(-\frac{1}{2}\) and \(\frac{3}{2}\)

Answer 8

then since this is a parabola that opens up, it is negative between the zeros and positive outside them
you want negative (less than zero) so it will be
\[-\frac{1}{2}<x<\frac{3}{2}\]