Write an appropriate direct variation equation if y = 8 when x = 2. *metals*
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OpenStudy (campbell_st):
well the basic direct variation equation is
y = kx
k is the constant of variation
so substituting
\[8 = k \times 2\]
what do you think the value of k is?
OpenStudy (anonymous):
y =16/x
y = 4x
y = 8x
y =4/x
(options)
OpenStudy (anonymous):
I think it's y=4x
OpenStudy (campbell_st):
well done
OpenStudy (anonymous):
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OpenStudy (campbell_st):
are you using the same direct variation equation...?
OpenStudy (anonymous):
I think so but it's graphing
OpenStudy (campbell_st):
well find the slope of the line....
and the slope will be the k value
OpenStudy (anonymous):
I think it's direct
OpenStudy (campbell_st):
opps... misread the equation.... because its a straight line its a direct variation
the value of k... is the slope of the line
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OpenStudy (anonymous):
so it's inverse
OpenStudy (campbell_st):
no, its direct.....
y = 1/3 x
OpenStudy (anonymous):
If y varies inversely as x, and y = 4 as x = 8, find y for the x-value of 2. (next work)