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Physics 8 Online
OpenStudy (anonymous):

Vitellium (Vi) has the following composition: Vi-188: 187.9122 amu; 10.861% Vi-191: 190.9047 amu; 12.428% Vi-193: 192.8938 amu; 76.711% Based on this data, what can you predict about the average atomic mass of vitellium?

OpenStudy (aaronq):

\(average~atomic~mass=\Sigma(m_{isotope~A}*\%~Abundance_{isotope~A}) \)

OpenStudy (aaronq):

in other words, find the weighted average of the data set.

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