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OpenStudy (anonymous):

Write a balanced net ionic equation for the principal reaction in solutions of each of the following salts. In each case, identify the Brønsted-Lowry acids and bases and the conjugate acid-base pairs. 1. Na_2CO_3 2. NH_4NO_3

OpenStudy (aaronq):

the question is asking you to predict the reactions: \(Na_2CO_3+H_2O\rightarrow \) \(NH_4NO_3+H_2O\rightarrow \)

OpenStudy (anonymous):

I get that half it is the other part besides the production of OH- that I don't have

OpenStudy (aaronq):

\(Na_2CO_3+H_2O→ NaOH + NaHCO_3\)

OpenStudy (aaronq):

for the net equation, remove the spectator ions

OpenStudy (anonymous):

It says missing the charge and also elements being substituted for another

OpenStudy (anonymous):

saying its incorrect

OpenStudy (aaronq):

did you remove the spectator ions before inputting your answer?

OpenStudy (anonymous):

No I guess I did not

OpenStudy (aaronq):

wait are you mixing both of the reagents, or just mixing them in water?

OpenStudy (anonymous):

water and its equilibrium problems. They are both separate problems sorry I didn't specify that

OpenStudy (aaronq):

oh okay, so yeah, the net should look like: \(CO_3^{2-}+H_2O→OH^-+HCO_3^-\)

OpenStudy (anonymous):

Okay and for the second one?

OpenStudy (aaronq):

the second one is \(NH_4^+\) acting as an acid.

OpenStudy (anonymous):

okay thanks a lot so it would be NH_4^+ + H_2O <=> OH^- + HNO_3^- ?

OpenStudy (aaronq):

nope, \(NH_4^+\) is an acid, you'll make hydronium ions

OpenStudy (anonymous):

okay I tried it and it was wrong, could you show me what it looks like as you did in the first one so I can better understand this one also?

OpenStudy (anonymous):

thanks for spending the time to help

OpenStudy (aaronq):

\(NH_4NO3+H_2O→H_3O^++NH_3+NO^-_3\) you need to remove the spectator ions

OpenStudy (aaronq):

no problem

OpenStudy (anonymous):

NO_3 + H_2O<=>H_3O^+ + NH_3. I put this in an it says it is incorrect. Did I do something wrong?

OpenStudy (aaronq):

\(NO_3^-\) is the spectator ion, \(NH_4^+\) is the acid.

OpenStudy (anonymous):

Oh ya shoot that was a typo. I got it now. Thanks again

OpenStudy (aaronq):

good stuff. no problem, work on identifying acids/bases

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