I really need help, if you know how to do this and can it explain how you got an answer that would be great cause I have no clue how to do this problem

NO2 is known to decompose via a second-order mechanism. If the half-life of this decomposition is 250 seconds when the initial concentration of NO2 is 0.75 M, what is the rate constant for this decomposition?
A) 0.0053 s-1
B) 190 s-1
C) 0.0027 s-1
D) 360 s-1

Question

I really need help, if you know how to do this and can it explain how you got an answer that would be great cause I have no clue how to do this problem

NO2 is known to decompose via a second-order mechanism. If the half-life of this decomposition is 250 seconds when the initial concentration of NO2 is 0.75 M, what is the rate constant for this decomposition?
A) 0.0053 s-1
B) 190 s-1
C) 0.0027 s-1
D) 360 s-1

aaronq · Answer

do you know the 2nd order rate law (formula)?

anonymous · Answer

yes there is two 1/ [A]t - 1/[A]o =kt and then t1/2 =1/k[A]o   i have tried using them but what throws me off is that they give and initial rate but no final and that's when i get lost

aaronq · Answer

use the second formula you posted. They didn't give you any rates.

aaronq · Answer

$t_{1/2}=\dfrac{1}{k[A]_o}$