The functions f(x) and g(x) are described using the following equation and table: f(x) = -3(1.02)x x g(x) -1 -5 0 -3 1 -1 2 1 Which statement best compares the y-intercepts of f(x) and g(x)? The y-intercept of f(x) is equal to the y-intercept of g(x). The y-intercept of f(x) is equal to 2 times the y-intercept of g(x). The y-intercept of g(x) is equal to 2 times the y-intercept of f(x). The y-intercept of g(x) is equal to 2 plus the y-intercept of f(x).
x= -1, 0, 1, 2 y= -5, -3, -1, 1
|dw:1395697729361:dw| so to find the y-intercept for f(x), set x =0, that is \(\bf y = -3(1.02)0\) and solve for "y" to find the y-intercept for g(x), just look at the table, see when "x" is 0,
So g(x)=-3 and f(x)=-3.06?
yeap
so the last one is right? maybe?
hmm I'd say none really, because none of the choices compare them well
-3 and -3.06 do not have a "2" as multiplier, just that one of 1.06 from the parentheses
so what one should i put for the answer
hmm wait... a sec... ... darn..
anyhow I guess my bad ... well... \(\bf f(x) = -3(1.02)0\implies f(x)=-3\cdot 0\implies f(x)=0\) still though
unless you meant \(\bf f(x) = -3(1.02)^x\)
yes
well, then recall that anything raised to 0, is 1
Okayy
\(\bf f(x) = -3(1.02)^x\implies f(x) = -3(1.02)^0\implies f(x) = -3\cdot 1 \\ \quad \\ \implies f(x) = -3\)
So a
yeap, they're both equal when x = 0 for f(x), the y-intercept is -3 from the table, for g(x) is the same
Thank you. Can you help me with another question?
you can always post anew, thus more exposure and we can revise each other
Okay
@hartnn could you help me with this one? i have the same table given up top but the equation i have is f(x)=-6(1.02)^x
to get y-intercept of f(x) , plug in x= 0 in f(x) what do u get ?
i got 1
no... f(0) = -6(1.02)^0 = ...?
anything to the power of zero is 1 i thought?
yes, but there is -6 too! f(0) = -6*1 = -6
oh!!!!!
so would the answer be B?
g(x) ---> -3 f(x) ----> -6 yes B :)
can you help me in another?(=
i can try :)
@hartnn
hello? @hartnn
f is 5^x g is -3 f+g will be 5^x -3
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