Find the exact value of sec(11pi/3) using reference angles.
I think a good start would be to convert sec into cos using the identity \[\sec(x) = \frac{1}{\cos(x)}\] have you tried that?
No lol that didnt come to me in my mind but it makes sense to do that
Cool, try that out and see if you can get it. Let us know if you get stuck! :)
im stuck still tho idk how to go on or what exactly to do
OK, so let's just focus on \[\cos(\frac{11 \pi}{3})\] for now.
Have you learned to use the unit circle?
yes i have
OK, that will make it a lot easier! :) Alright, now let's try and figure out where the angle 11pi/3 will land on the unit circle. Remember that whenever we get 2pi we've gone around the whole circle.
11pi/3 is 660 degrees. cos(660 degrees) = cos(300 degrees)
ok i know the terminal point of 11pi/3 is (1/2, -sqrt3/2)
good!
Remember then that the cosine value matches the x-coordinate, so what is the value of our cosine?
1/2
correct! :D
Alright, so we now know that \[\cos(\frac{11 \pi}{3}) = \frac{1}{2}\]
But, of course, we wanted to know what secant was. So, we just need to divide 1 by 1/2 in the beginning.
So, \[\frac{1}{1/2} = 1 \div \frac{1}{2} = 1 \times \frac{2}{1} = 2\]
and there's our answer! does that make sense? anything you want to clarify? :)
That makes perfect sense actually thank you! :)
great job!
Thank you!
yw
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