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Chemistry 14 Online
OpenStudy (anonymous):

Write the balanced chemical equation, the complete ionic equation, and the net ionic equation for the following: Li2SO4(aq)+Ca(NO3)2(aq)->LiNO3(aq)+CaSO4(s)

OpenStudy (ipwnbunnies):

For a complete ionic equation, you wanna expand the aqeous(?) solutions into their respective ion forms, but you keep insoluble compounds as is.

OpenStudy (ipwnbunnies):

For net ionic equation, you look at the complete ionic equation. Then, cancel out the things that appear in the reactants and the products.

OpenStudy (ipwnbunnies):

I'll do the first part of the complete ionic eq: 2 Li+ (aq) + SO4 (aq) + ...

OpenStudy (ipwnbunnies):

SO4 has a 2- ion charge* Forgot to put that in next to the SO4

OpenStudy (anonymous):

+Ca2+(NO3-)2-->2Li+NO3- +CaSO4

OpenStudy (ipwnbunnies):

For the NO3, the '2' will actually go out front. '2 NO3- (aq)'

OpenStudy (ipwnbunnies):

Oh yeah, I forgot, include the state of matter. Aqueous solutions stay aqueous, and keep the solids, liquids, etc. if there are any in the products.

OpenStudy (ipwnbunnies):

Your products are right, just include the states of matter lol.

OpenStudy (anonymous):

Okay, thanks.

OpenStudy (ipwnbunnies):

Noooo, you forgot to add '2' to the nitrate in the products too, lol

OpenStudy (anonymous):

For the net ionic equation, would SO4 be the only one used on both sides; the spectator ion

OpenStudy (ipwnbunnies):

Right, keep the SO4, but also keep the Ca because it's part of the solid in the product. For net ionic eqs, cancel out the spectator ions.

OpenStudy (ipwnbunnies):

If the ions are EXACTLY alike in both sides, they are spectator ions.

OpenStudy (anonymous):

So, even though the "Ca" on the first side is plus 2 , its still the same?

OpenStudy (ipwnbunnies):

Yeah. The Ca 2+ ion bonds with the SO4 2- ion to make the sulfate in the product, which is insoluble.

OpenStudy (anonymous):

Oh okay. I got it. It was just my lazy mistake. Thanks.

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