Question

What is the Pythagorean Theorem?

Answer 1

\(\ a^2 + b^2 = c^2 \)

Answer 2

For any right triangle ABC where B is the right angle, AB^2+BC^2=AC^2

Answer 3

Thanks! Can you help with #5 on this link? https://lss.brainhoney.com/Resource/12429854,101,45,36,0/Assets/Honors%20Geometry%20Part%20A%20First%20Semester%20Final%20Form%20A.pdf?attachment=1

Answer 4

C being the hypotenuses

Answer 5

I need help with #5 on this link https://lss.brainhoney.com/Resource/12429854,101,45,36,0/Assets/Honors%20Geometry%20Part%20A%20First%20Semester%20Final%20Form%20A.pdf?attachment=1 @tHe_FiZiCx99 @kc_kennylau

Answer 6

not to be pedantic, but \(a^2+b^2=c^2\) is an equation, not a theorem
as an equation it is either true or false, depending on the values of \(a,b,c\)
for example \(3^2+4^2=5^2\) is true, while \(5^2+6^2=7^2\) is false

Answer 7

@satellite73 thanks for that clarification! can you help with #5 on the link above? :)

Answer 8

True, but normally C has to be greater for it to be correct. It's the longer part of the triangle's leg.

Answer 9

looks like
\[4x+14=6x\]

Answer 10

that is wrong, i mean
\[4x+14+31=6x\]

Answer 11

Um, wouldn't it be 4x + 45 = 6x?

Answer 12

your job is to solve for \(x\) which is pure algebra, no geometry

Answer 13

ok...

Answer 14

can one of you help with #6 on this link? https://lss.brainhoney.com/Resource/12429854,101,45,36,0/Assets/Honors%20Geometry%20Part%20A%20First%20Semester%20Final%20Form%20A.pdf?attachment=1

Answer 15

start by adding to get
\[4x+45=6x\] subtract \(4x\) get
\[45=2x\] then divide by 2

Answer 16

sorry, i am on #6, now :)

Answer 17

@satellite73

Answer 18

No it isn't @Akash321

Answer 19

how?

Answer 20

idk, but i just looked up the answer and everyone said it is 135, A

Answer 21

._.

Answer 22

Satellite and I gave you the equation that you needed to solve for -- x. Do so and you'll get your answer

Answer 23

work that equation n u will have 22.5, try it