Question

Can anybody give me two example problems similar to...
A bag contains hair ribbons for a spirit rally. the bag contains 4 black ribbons and 11 green ribbons.Lila selects a ribbon at random from the remaining ribbons. what is the probability that Lila selects a black ribbon and Jessica selects a green ribbon?

Answer 1

@phi Can you help me with this please?

Answer 2

8/15 *7/14 =

Answer 3

@BeautifulMelodies I just need two similar examples to this problem (:

Answer 4

In Experiment 1 the probability of each outcome is always the same. The probability of landing on each color of the spinner is always one fourth. In Experiment 2, the probability of rolling each number on the die is always one sixth. In both of these experiments, the outcomes are equally likely to occur. Let's look at an experiment in which the outcomes are not equally likely.

Experiment 3: A glass jar contains 6 red, 5 green, 8 blue and 3 yellow marbles. If a single marble is chosen at random from the jar, what is the probability of choosing a red marble? a green marble? a blue marble? a yellow marble?
Outcomes: The possible outcomes of this experiment are red, green, blue and yellow.
Probabilities: P(red) = # of ways to choose red = 6 = 3
total # of marbles 22 11

P(green) = # of ways to choose green = 5
total # of marbles 22

P(blue) = # of ways to choose blue = 8 = 4
total # of marbles 22 11

P(yellow) = # of ways to choose yellow = 3
total # of marbles 22

Answer 5

Experiment 4: Choose a number at random from 1 to 5. What is the probability of each outcome? What is the probability that the number chosen is even? What is the probability that the number chosen is odd?
Outcomes: The possible outcomes of this experiment are 1, 2, 3, 4 and 5.
Probabilities: P(1) = # of ways to choose a 1 = 1
total # of numbers 5

P(2) = # of ways to choose a 2 = 1
total # of numbers 5

P(3) = # of ways to choose a 3 = 1
total # of numbers 5

P(4) = # of ways to choose a 4 = 1
total # of numbers 5

P(5) = # of ways to choose a 5 = 1
total # of numbers 5

P(even) = # of ways to choose an even number = 2
total # of numbers 5

P(odd) = # of ways to choose an odd number = 3
total # of numbers 5


The outcomes 1, 2, 3, 4 and 5 are equally likely to occur as a result of this experiment. However, the events even and odd are not equally likely to occur, since there are 3 odd numbers and only 2 even numbers from 1 to 5.

Answer 6

@BeautifulMelodies Could you please give me one more example please?

Answer 7

Experiment 1: A spinner has 4 equal sectors colored yellow, blue, green and red. After spinning the spinner, what is the probability of landing on each color?
Outcomes: The possible outcomes of this experiment are yellow, blue, green, and red.
Probabilities: P(yellow) = # of ways to land on yellow = 1
total # of colors 4

P(blue) = # of ways to land on blue = 1
total # of colors 4

P(green) = # of ways to land on green = 1
total # of colors 4

P(red) = # of ways to land on red = 1
total # of colors 4

Answer 8

Thankyou! Could you help me fine a couple more examples please? If you don't mind. (:

Answer 9

I actually have work to do :(

Answer 10

It's totally fine! Thank you for your help!

Answer 11

You're welcome :)

Answer 12

@BeautifulMelodies wait sorry but for the second examle you gave me ..How eould you get the final answer?

Answer 13

The outcomes 1, 2, 3, 4 and 5 are equally likely to occur as a result of this experiment. However, the events even and odd are not equally likely to occur, since there are 3 odd numbers and only 2 even numbers from 1 to 5.


my bad :)