Question

Someone check my work please!

Answer 1

Hold on, let me write it first

Answer 2

\[\log _{b ^{n}}=\frac{ 1 }{ n }\log _{b}x\]

Answer 3

Basically, I'm supposed to prove that these two are the same, let me show my work

Answer 4

Where's the x in the LHS?

Answer 5

\[\frac{ \log _{b}x }{ \log _{b} (b ^{n} )}=\frac{ \log _{b} x}{ nlog _{b}b}\]

Answer 6

crud @primeralph I forgot the x, sorry x_x

Answer 7

Crud?

Answer 8

crud=darn (at least for me)

Answer 9

Okay, just correct the equation.

Answer 10

\[\log _{b ^{n}}x=\frac{ 1 }{ n }\log _{b}x\]
^
That is the correct equation. Terribly sorry

Answer 11

and rem my final step in the process of proving this statement was: \[_{}\frac{ \log _{b} x}{ n }=\frac{ 1 }{ n }\log_bx\]

Answer 12

Does this make any sense to anyone looking at this? >.<

Answer 13

Try proving it sequentially.

Answer 14

sequentially? O_O erm what do you mean?

Answer 15

In order.

Answer 16

Step by step; with logic. And don't bother using LatTex

Answer 17

I mean, I know this is a true statement, but proving things has always been a hassle for me. This time, I'll try to put the entire proof in one comment :P and I won't bother with \(\LaTeX\) this time

Answer 18

I never asked you to put it all in one comment. Just explain the logic behind what you do.

Answer 19

Ohh okay, I see.

So I already wrote out the original equation several times (albeit incorrectly the first time), but I'll do it again: log (b_n)x=1/2log_b x

This is what I am being asked to prove.

Answer 20

1/2?

Answer 21

Just draw it out.

Answer 22

no, erm 1/n

and lol will do i suppose