Question

This is a log. problem that really doesn't make much sense to me.

Answer 1

http://prntscr.com/33voyw

Answer 2

evaluate them one by one it's easy

Answer 3

The time goes by
So naturally
Why you'll receive
Infinity

Answer 4

what do you mean? not sure what to do with the logs. that have different bases...would you just change all the bases to base 10? and @iambatman wuut? O_O

Answer 5

Honestly, I feel like I'm overthinking this. lol this is the first problem on my worksheet, and I was able to solve the latter problems with little trouble.

Answer 6

first find \[\log_{2} 32\]
which equal \[\log_{2} 2^{5}=5\log_{2} 2=5(1)=5\]

Answer 7

so it will be
\[\log_{12}(\log_{9}(\log_{5}5)) \]

Answer 8

So basically, \(\log_2 32\)=\(5\) right? and then you would plug it in to all the other logs! Wow that was really easy...embarrassingly easy darn I knew I was overthinking it! Here I'll try to solve it on my own and then I'll come back with the answer, please let me know if I'm correct.

Answer 9

The time goes by
So naturally
Why you'll receive
Infinity

Answer 10

let
\[\log_{2} 32=x,2^x=32=2^5,x=5\]
let
\[\log_{5} 5=y,5^y=5,5^y=5^1,y=1\]
let
\[\log_{9} 1=t,9^t=1=9^0,t=0\]
let
\[\log_{12} 0=r,12^r=0=\frac{ 1 }{12^{\infty} } =12^{-\infty },r=-\infty \]

Answer 11

:)

Answer 12

wow thanks guys! *_*

Answer 13

Yeah I was hinting the final answer haha :p

Answer 14

*gasp* but this is against the rules! You know, no ansurs :P LOL

Answer 15

yw

Answer 16

I didn't directly give you the answer ^.^ haha, was saying it'll "naturally" lead you to it haha. Well done @surjithayer

Answer 17

I see... >_> hmm, I'll let that slide this time.
just kidding, well done with your incognito hints!

Answer 18

Haha, thanks, but surj did a great job explaining it :)

Answer 19

he really did O_O I'm impressed