integral from 0 to infinit for 1/x^(1/4) Please help! just wanna check my answer, I got 0
\(\int_0^\infty x^{-\frac{1}{4}}dx=\frac{4}{3}x^{\frac{3}{4}}|_0^\infty=\infty\)
isn't infinity^3/4 = 0
no
\(\sqrt{\infty}=\infty\)
if exponent is negative then infinity^n = 0
oh ok so then the integral from 1 to infinity would be infinity aswell cause for that I get 4/3infnity^3/4-4/3
\(\frac{4}{3}\infty^\frac{3}{4}-\frac{4}{3}*0^\frac{3}{4}=\frac{4}{3}\infty^\frac{3}{4}=\infty\)
ok thanks!
yes
I see what you are saying...
for any n that is not infinity, negative inifinty
you will either subtract or add a finite amount to infinity, so you will get infinity
and infinity - infinity does not even make sense.....
and also I did the integral from 1 to infinityof 1/x^(1/4) if I use p integral rule 1/p-1 I get - 4/3 but if I solve analyticaly and if infinity ^4/3=infinity then I get 0 so that's why im confused
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