integral from 0 to infinit for 1/x^(1/4)
Please help! just wanna check my answer, I got 0

Question

zzr0ck3r · Answer

$\int_0^\infty x^{-\frac{1}{4}}dx=\frac{4}{3}x^{\frac{3}{4}}|_0^\infty=\infty$

anonymous · Answer

isn't infinity^3/4 = 0

zzr0ck3r · Answer

no

zzr0ck3r · Answer

$\sqrt{\infty}=\infty$

dumbcow · Answer

if exponent is negative then infinity^n = 0

anonymous · Answer

oh ok so then the integral from 1 to infinity would be infinity aswell
cause for that I get 4/3infnity^3/4-4/3

zzr0ck3r · Answer

$\frac{4}{3}\infty^\frac{3}{4}-\frac{4}{3}*0^\frac{3}{4}=\frac{4}{3}\infty^\frac{3}{4}=\infty$

anonymous · Answer

ok thanks!

zzr0ck3r · Answer

yes

zzr0ck3r · Answer

I see what you are saying...

zzr0ck3r · Answer

for any n that is not infinity, negative inifinty

zzr0ck3r · Answer

you will either subtract or add a finite amount to infinity, so you will get infinity

zzr0ck3r · Answer

and infinity - infinity does not even make sense.....

anonymous · Answer

and also I did the integral from 1 to infinityof 1/x^(1/4) if I use p integral rule 1/p-1 I get - 4/3 
but if I solve analyticaly and if infinity ^4/3=infinity then I get 0 so that's why im confused