An alkane with the formula C6H14 can be prepared by reduction (with Zn and HCl) of only two
alkyl chlorides (C6H13Cl) and by the hydrogenation of only two alkenes (C6H12). Write the structure of
this alkane, give its IUPAC name. And show the reactions.

Question

An alkane with the formula C6H14 can be prepared by reduction (with Zn and HCl) of only two
alkyl chlorides (C6H13Cl) and by the hydrogenation of only two alkenes (C6H12). Write the structure of
this alkane, give its IUPAC name. And show the reactions.

anonymous · Answer

Iupac name of C6H14 is Hexane.
Structure is given in pic.
C6H13CL  + Zn + HCl --->  C6H14 + ZnCl2
C6H12 + H2 --Ni (200-300 C)-->  C6H14
Ni is catalyst and 200-300 is temperature

gebooors · Answer

Position of double bond causes that
C6H12 can be 1-hexene or 2-hexene.
That's why there is two possible alkenes.