Question

I Need help on one question may anyone solve this step by step for me. #27

Answer 1

*thanks

Answer 2

you must use here
\[\sqrt{a^2} = a\]
\[a \sqrt{b}.c \sqrt{d} = ac \sqrt{bd}\]

Answer 3

so lets see each term alone first

\[\sqrt{7x^2}= ?\]

Answer 4

ok

Answer 5

do you know this \[\sqrt{7x^2} = ?\]
?

Answer 6

x√ 7?

Answer 7

yeah that's right

now
\[\sqrt{28x^3} =?\]

Answer 8

2x√ 7x

Answer 9

great!
so now we have

\[-2(x \sqrt{7})\frac{ 1 }{ 3 }(2x \sqrt{7x})\]

do you know how to simplify this ?

Answer 10

− 28x^2 x√/ 3 Sorry if that makes since cant write itt out like u lol

Answer 11

− 28x^2 √x/ 3 ?

Answer 12

im sorry i typed it all crazy

Answer 13

Well can u write it for me step by step so i can write it neatly

Answer 14

lol
you can use the "Equation" by clicking on the bottom left key "Equation" it makes it clearer :P

but you got the answer right
good job! :)

Answer 15

Thank you well will u write itt from the problem and how we solved it all in one message please so i dont right it wrong. please. i need to write the problem out

Answer 16

\[-2\sqrt{7x^2} \frac{ 1 }{ 3 }\sqrt{28x^3} = -2(x \sqrt{7}) \frac{ 1 }{ 3 }(\sqrt{7(2^2)xx^2}) = -\frac{ 2x }{ 3 }\sqrt{7}[2x \sqrt{7x}]\]
\[= -\frac{ 4x^2 }{ 3 }\sqrt{7^2x} = -\frac{ 28x^2 }{ 3 }\sqrt{x}\]

Answer 17

thnkz

Answer 18

is it good like this ?

Answer 19

ya

Answer 20

glad to help :)