Question

25^(x-1) = 125^(4x)

solve for x. i will post a picture to make it easier to read

Answer 1

\[25^{(x-1)} = 125^{(4x)}\]

Answer 2

how to find x??

Answer 3

NICE FORMATTING! THANKS!
I'd suggest you write both 25 and 125 as powers of 5.
for example, 25=5^2.

Then 125=5^?

Then the left side becomes (5^2)^(x-1). What about the right side?

Once you have both sides expressed as powers of 5, you can drop the base 5, set the two exponents equal to each other, and solve for x. Good luck!

Answer 4

\[5^{2^{(x-1)}} = 5^{3^{4x}}\]

Answer 5

is that it?? @mathmale

Answer 6

wt would be my next step?

Answer 7

wiat is the answer, x=-1/3

Answer 8

Nice work. Just a bit of format fixing: The exponent on the left should be 2(x-1) (NO exponentiation here); the exponent on the right should be 12x

Answer 9

ooooh ok! thx :)

Answer 10

You can check your answer yourself by substituting your x=-1/3 into the original equation. Is the resulting equation true or false?

Answer 11

oh ok I got it thx :)