Question

The bearcat school store is running a promotion on school supplies .Difference items are placed on two shelves .You can purchase 3 items from shelf M and 2 from shelf N for $16.Or you can purchase 2 item from shelf M and 3 from shelf M for $14 .If the supplies on shelf M are normally $ 6 each and the supplies on shelf N are normally $ 3, how much will you save on each package pan from part M ?

3M+2N = 16
2M+3N = 14

Answer 1

okay

Answer 2

that the equation , but how I answer the question?

Answer 3

not finsh yet

Answer 4

first plug in the N, so you can find the M

Answer 5

give M=6
N = 3

Answer 6

then subtract M from the original price of M to find the save you are making

Answer 7

2M + 3(3) = 14
2M + 9 = 14
2M = 5
M = 2.5
(Original M) - 2.5 = saving

Answer 8

I did the second equation

Answer 9

Now do the first.

Answer 10

Original M = 6

Answer 11

I don't get it

Answer 12

but the given give both M and N
M=6
N = 3
you don't plus M?

Answer 13

Wait, sorry

Answer 14

I gave you wrong info

Answer 15

Why not do the elimination method to find M

Answer 16

to both equations

Answer 17

if you do elimination method. M =4

Answer 18

\[3M+2N = 16 \\]
\[2M+3N = 14\]

Answer 19

the resut I did M=4
N = 2
but the given give both M and N
M=6
N = 3
I think the question don't want use the resut, requite use M=6 , N=3

Answer 20

N, the question wants to know what the saving are from M on the package deals.

Answer 21

and you found that M = 4 on the package deals

Answer 22

So, 2 dollars would be the price you saved for M

Answer 23

yes I did get answer : M=4
N = 2
but the question gien: M=6
N=3

Answer 24

what you do with : M=6
N =3
?