Which value of B solves the equation?
B^-3=1/27
A.
3
B.
27
C.
9
D.
81
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OpenStudy (anonymous):
I'll help
OpenStudy (anonymous):
C
OpenStudy (anonymous):
@cowgirlcrazy66, @lind3
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
\[\frac{ 1 }{ B ^{3} } = \frac{ 1 }{ 27 }\]
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OpenStudy (anonymous):
B = 3
OpenStudy (anonymous):
oh sorry, not C
OpenStudy (anonymous):
I believe it's A
OpenStudy (anonymous):
Yes, it's A
OpenStudy (anonymous):
Sorrry
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OpenStudy (anonymous):
If you have a negative exponent in the numerator, it will be positive in the denominator. Re-write your equation first as @faisalalif1999 showed you a few posts up.
OpenStudy (anonymous):
ok thank you a lot!!!
OpenStudy (anonymous):
If you square the 3 with -3 you will get the same exact answer with 1/27
OpenStudy (anonymous):
Yes it's A.
OpenStudy (anonymous):
thx!!!!!!
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OpenStudy (anonymous):
No problem!
OpenStudy (anonymous):
B=3 my friend @whitetiger2288
OpenStudy (anonymous):
ok thanks!
OpenStudy (anonymous):
(NP)
OpenStudy (anonymous):
B = 3! Let's see how long we can keep this thread alive.
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OpenStudy (anonymous):
LOL
OpenStudy (anonymous):
You have:
\[B^{-3} = \frac{1}{27}\]
We can re-write this as:
\[\frac{1}{B^3} = \frac{1}{27}\]
If we multiply both sides by 27 and B^3:
\[27 \times B^3 \times \frac{1}{B^3} = \frac{1}{27}\times 27 \times B^3[\]
we have
\[27 = B^3\]
Taking the cube-root of both sides:
\[\sqrt[3]{27} = \sqrt[3]{B^3}\]
we get:
\[3 = B\]
which is
\[B = 3\]
OpenStudy (anonymous):
In english, your answer is "B is equivalent to three," or "B is equal to three."
OpenStudy (anonymous):
whitetiger what time is it were you are?
OpenStudy (anonymous):
Translated to German, that is "B ist gleich drei."
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OpenStudy (anonymous):
Whitetiger I have to go to bed but I will be online all day so talk to you tomorrow!!! BYE BYE