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Given the sequence 2, 8, 32, 128, 512 … , what is S10 ?
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524,288
That's what i got but its not in the multiple choice answers.. :( A. 174,762 B. 699,050 C. 2,796,202 D. 1,073,741,823
\(\sum_{n=1}^{10}2^{2n-1}=699050\)
Well i guess this guy is right.
So its B... Im still confused on how though to be honest.
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do you get why I used \(2^{2n-1}\)?
Yeah.. i think.
well then, what is confusing? I just added them up
Okay now i get it. I guess I was confused on how you found that in the first place.... but i get it now. Thanks!
\(2^{2*1-1}+2^{2*2-1}+.....+2^{2*10-1}\)
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np
you just have to see the pattern we have 2 = 2^1 8=2^3 32=2^5 ..... so we needed something that would index 1,3,5.... and 2n-1 will do that.
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