Question

Logarithmic equation

.3 = x + 10^(-14)*e^(x/.026)

Answer 1

\(.3=x+\frac{e^\frac{x}{.026}}{10^{14}}\)?

Answer 2

\[.3 = x + 10^{-14}e ^{\frac{ x }{ .026 }}\]

Answer 3

yah

Answer 4

hmm, not sure if you can solve this.

Answer 5

yah not sure how to do it because if you take the log of both sides then the lone x gets messed up and vice versa

Answer 6

the answer is way above my pay grade.
https://www.wolframalpha.com/input/?i=.3+%3D+x+%2B+10^%28-14%29*e^%28x%2F.026%29

scroll down to where it says solution

Answer 7

the answer is .3 but not sure how they got it

Answer 8

thats an approximate, they used the link I sent you.

Answer 9

there is no basic analytic way to solve this, you need to be pretty high up there is math to solve it.

Answer 10

take x on LHs and solve it . you will get something like
\[\log(.3-x) = y \]


now you will sovle it by taking antilog

Answer 11

lol yah it seems whatever is on the left hand side is the answer as long as it is within the domain

Answer 12

its like solving this
3^x = 2x

Answer 13

@crazysingh that wont work, keep going and you will see.

Answer 14

wait let me solve than @zzr0ck3r

Answer 15

ok:)

Answer 16

lol

Answer 17

10^(-14) is a very very small number close to zero and it can be ignored leaving you with x = 0.3

Answer 18

@ranga yah that is what i'm thinking

Answer 19

this is for an electrical circuits class so that is usually what they do with this kind of stuff anyhow

Answer 20

if the number is small enough then ignore

Answer 21

ok i think i'm just going to go with that. thank you veruy much everyone

Answer 22

You are welcome.

Answer 23

\(x\approx0.002(150-13*W_n\frac{e^{\frac{150}{13}}}{2600000000000})\) where W is the analytic continuation of the product log function and n is natural

Answer 24

i have no idea what that means:)

Answer 25

yah that is way over my head

Answer 26

lol