A class has 3 blonde students, 5 brown haired students, and 6 black haired students. How many ways can you arrange all the students?
14! ways of arranging 14 people. people with the same colored hair are still different people... so I don't know how the number of blondes vs brown vs black matter.
isn't this a combination ?
The wording in the problem is extremely poor, as phi indicated. Are we to take each person as a unique individual, or do we assume hair color is the only factor we are counting? Also, are they asking how many different groups of any size can be formed, or do we have to use all the people each time, or...?
Your question are quite valid - and the questions I too asked when I tried to solve this problem. The wording is very ambiguous. He said we should be able to figure it out.
Since it is 14 different people, maybe it should just be 14! ?
that seems to be the only logical answer to me, as well.
Thank you all for your help. I appreciate it.
Poorly worded, as others pointed out. I believe the answer is not 14!, but we count people of hair colour as the same.
So divide by 3! * 5! * 6!
Getting hole in memory but agreeing it what we call arrangement in french so 14!
I had also considered that option as well. I'm wondering if maybe you are correct on this, since he did list that some of the students have the same hair color.
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