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Factor the following problem completely. First, factor out the greatest common factor, and then factor the remaining trinomial: 2r^3 + 8r^2 - 24r
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\[ 2r^3 + 8r^2 - 24r = 2r(r^2 + 4r - 12) = 2r(r + 6)(r - 2) \]
I guessed the last step, but it is possible to do it without guessing. Solve \(r^2 + 4r - 12 = 0\) to get two roots \(r_1\) and \(r_2\). \(r^2 + 4r - 12\) may then be factored as \((r - r_1)(r - r_2)\).
Correct! Thank you, next question.
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