Question

Find f"(x) for each function. Then find f"(0) and f"(2)
f(x)=-x/1-x^2

Answer 1

\(\frac{-x}{1-x^2}\)?

Answer 2

Yes

Answer 3

do you know how to find the first derivative?

Answer 4

no

Answer 5

i missed the lesson
about this

Answer 6

\((\frac{f(x)}{g(x)})'=\frac{f'(x)g(x)-g'(x)f(x)}{(g(x))^2}\)

Answer 7

so you have
\(f(x) = -x, g(x) = 1-x^2\)

Answer 8

okay

Answer 9

\(f'(x)=-1,g'(x)=-2x
\)so
\((\frac{-x}{1-x^2})'=\frac{-1(1-x^2)-(-2x)(-x)}{(1-x^2)^2}\)now simplify

Answer 10

how did 1-x^2 turned to -2x

Answer 11

i dont know how to simplify this

Answer 12

you need to go back and review, it seems you are not at the level you shuold be to do these problems

if f(x) = 1-x^2
then f'(x) = -2x

Answer 13

okay now simplifying this problem will be (-1+1x^2)+(2x+1)/1-x^4

Answer 14

am i correct

Answer 15

@jdoe0001

Answer 16

@@AccessDenied @eyust707

Answer 17

I need help simplifying this