Given the following equations, calculate the (triangle symbol)H of reaction of ethylene gas (C2H4) with fluorine gas to make carbon tetrafluoride (CF4) gas and hydrogen fluoride gas. Show your work.
H2 (g) + F2 (g) -- 2HF (g) (Triangle symbol)H= -537 kJ
C (s) + 2F2 (g) -- CF4 (g) (Triangle symbol)H= -680 kJ
2C (s) + 2H2 (g) -- C2H4 (g) (Triangle symbol)H= +52.3 kJ

This is my last question and I don't really understand how to do this.

Question

Given the following equations, calculate the (triangle symbol)H of reaction of ethylene gas (C2H4) with fluorine gas to make carbon tetrafluoride (CF4) gas and hydrogen fluoride gas. Show your work.
H2 (g) + F2 (g) --> 2HF (g) (Triangle symbol)H= -537 kJ
C (s) + 2F2 (g) --> CF4 (g) (Triangle symbol)H= -680 kJ
2C (s) + 2H2 (g) --> C2H4 (g) (Triangle symbol)H= +52.3 kJ

This is my last question and I don't really understand how to do this.

gebooors · Answer

Reaction is. C2H2 + 5 F2. -> 2 CF4 + 2 HF

Triangle symbol = delta

Entalpies of formation of substances are given.
For F2 it is zero, because it is element.

Delta H = delta H (products)  - delta H (start substances)
Remember multiply with number of moles.

ria23 · Answer

I'm, not really sure what I'm supposed to do, could yhu walk me through this?