Question

smallest value of speed

Answer 1

v(t)= <3cos3t, -3sin3t, 4cos4t>

Answer 2

so |v(t)|= \[\sqrt{9\cos^2(3t)+9\sin^2(3t)+4\cos^2(4t)}\]

Answer 3

simplifing 9cos^2(3t) + 9sin^2(3t), what do you get?

Answer 4

uh.. nope

Answer 5

i am not sure

Answer 6

lol i mean 9

Answer 7

good, so |v'(t)| = sqrt(9 + 16cos^2(3t)) yes? You forgot to square the 4

Answer 8

well, cos(0) = 1

Answer 9

Actually 5 is the maximum -.-

Answer 10

3 is indeed the minimum, but it's not at t = 0

Answer 11

hmm but ans=3

Answer 12

yup

Answer 13

so t=pi/2

Answer 14

yes, i corrected my mistake. 3 is the minimum but not at t = 0