Question

3x+4y=19
3x+6y=33
solve the system by elmination

Answer 1

3x + 4y = 19
3x + 6y = 33 -->(-1)
----------------
3x + 4y = 19
-3x - 6y = -33 (result of multiplying by -1)
-----------add
-2y = - 14
y = 7
now sub 7 in for y in either equation to find x
3x + 4y = 19
3x + 4(7) = 19
3x + 28 = 19
3x = 19 - 28
3x = - 9
x = -3

check..
3x + 6y = 33
3(-3) + 6(6) = 33
-9 + 42 = 33
33 = 33 (correct)

x = -3 and y = 7

Answer 2

Let's solve for y first.
\[3x+4y=19\] \[3x+6y=33\]
\[2y=14\] \[y=7\]

Let's look at x

\[3x+28=19\] \[3x=-9\] \[x=-3\]

\[3x+42=33\]
\[3x=-9\]
\[x=-3\]

Let's plug this back into the equations to check out work.

\[3(-3)+4(7)=19 \] \[3(-3)+6(-7)=33\]

It works! So, x=-3 and y=-7

I hope this helped!

Answer 3

oops..I messed up on the checking part
3x + 6y = 33
3(-3) + 6(7) = 33
-9 + 42 = 33
33 = 33 (correct)

x = -3 and y = 7

Answer 4

I meant 7, not -7. (Typo!!)

Answer 5

lol...a lot of typos here...but the answers are correct :)

Answer 6

thankss