Calculus question! Need help ASAP!!

The base of a solid is the area bounded by the curves y=x^2 and y=3x. Cross sections perpendicular to the x-axis are isosceles right triangles with one leg in the base. Find the volume of the solid.

Question

Calculus question! Need help ASAP!!

The base of a solid is the area bounded by the curves y=x^2 and y=3x.  Cross sections perpendicular to the x-axis are isosceles right triangles with one leg in the base. Find the volume of the solid.

anonymous · Answer

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anonymous · Answer

side = (3x - x^2)

anonymous · Answer

I'm supposed to find it using disc method, washer method, or shell method.

anonymous · Answer

you can't. This solid isn't formed by rotating the bounded region around any particular line

anonymous · Answer

V = ∫ area of cross section

V = ∫ (1/2) base * height

V = ∫ (1/2) (3x-x^2) (3x-x^2) dx, from 0 to 3

anonymous · Answer

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anonymous · Answer

So you don't multiply pi to the area? How do you find the base and height? How did you know the upper function?

anonymous · Answer

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