For the following series circuit, compute the power in R1, R2, and R3 if the circuit values are E = 24 volts, R1 = 8, R2= 12, and R3 = 28.
Hi. Long time since I did anything like this, but see if this looks OK... Resistances are in series, so total resistance of circuit, Rtot, is given by Rtot=R1+R2+R3 Therefore, Rtot=48 ohm Current in circuit, I, is given by I=V/R, where V=voltage, R=resistance Therefore I=0.5 amp P=Isquared R, where P=power Therefore, in R1, P=2 watt; in R2, P=3 watt; and in R3, P=7 watt My first post - only found this site a few minutes ago. Next time I'll use the equation-writing tool. Best regards.
Thank you!! This section is killing me so any help whatsoever is appreciated.
Happy to help. I was great at UK school physics to age 16, lousy at it from 16 to 18. Fortunately, I did circuit stuff when I was 15.
Wow, you did this stuff when you were young, and you had to do it for three years? I'm dying with just one.
Did two years at what was then called O-level (O for ordinary), and then two years at what's still called A-level (A for advanced). Ouch to the second one.
Physics wasn't compulsory at either stage. My pick x2.
Ahh cool. Unfortunately my school has very limited options for classes so we don't have anything like that.
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