please help
5. simplify the radical expression \[\sqrt{490y ^{5}}w ^{6}\]
First take out the variables. y^2 times y^2 equals y^4, therefore it can be taken out of the square root sign and one y is left. Same with w^3. For 490, you would need to break it down to 49 times 10, then take 49 out because the square root of 49 is 7. Are you following?
yes
So it would look like 7y^2w^3(square root sign)10y
okay :)
ok can you help me with a other one
sure thing
6. \[\sqrt{21y}*5\sqrt{49y}\]
Hm... you can simplify the second part by taking the square root of 49 (which is 7) and multiplying 7 by 5 to get 35 on the outside and leaving y on the inside. I'm not quite sure where to go from there though... hold on a sec
ok
Here's a good link on multiplying radicals: http://www.wikihow.com/Multiply-Radicals I will try to explain. Firstly, you can only multiply radicals of the same degree (square root, cube root, etc.). Then you just multiply what's in the radical together. Same thing with the outside numbers. In your example, you would multiply 21y by y to get 21y^2 on the inside and 35 on the outside, and take y out since it's squared. Your answer will be: 35y(square root sign)21
ok can you do another one
3.\[\sqrt{45}\]
Two factors of 45 are 9 times 5 and since 9 has a perfect square root, it can be taken out. Answer: 3(square root sign)5
ok a couple more
haha ok
4.\[\sqrt{56x^{2}}\]
2x(square root sign)14
7.\[\sqrt{\frac{ 63x ^{15y ^{9}} }{ 7xy ^{11}}}\]
8.\[\sqrt{3}+4\sqrt{3}\]
@Abbles you there
8. is 5(square root)3
ok
9.\[3\sqrt{5}+6\sqrt{45}\]
21(square root)5
How many do you have left?
8
ok do you understand how to do them now?
Do you know how to take square roots?
10.\[(8+\sqrt{11})(8-\sqrt{11})\]
Do you know how to do FOIL?
no
Okay, so start by multiplying the first term by everything in the second set of parenthesis. 8 times 8, 8 times (sqrt)11, so on. The answer to #10 is: 64 - 2(sqrt)33
Hey, can you give me a medal..? :)
thanks, any more questions?
ya 13.\[\sqrt{5x-1}=\sqrt{4x+9}\]
You can cancel out the square roots since they're both on each side. Then solve like normal. Answer is: x = y + 1 .... that is assuming you want the value for x and not y
Otherwise it would be: y = x - 1
ok
11.\[4=\sqrt{p}-2\]
p = 36
ok
12.\[\sqrt{x+3}=3\]
x = 6
Hey, I've gotta fun... do you think you can figure out the rest with the link I sent you? When are these questions due, I can help later tonight
ok
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