What is y = 5/2 in standard form?
I may be wrong, but I think that is in standard form. If not, you have to move everything to one side so you'll get 0 on one side.
Wait, is that y = 5/2 or y = 5/2x?
Just y = 5/2 this is slope intercept form. I need it in standard form
Slope intercept form: y = mx + b. Then that must be 5/2x, right?
Well, y = 5/2 is a horizontal line. That's why I'm saying it might already be in standard form. There's no independent variable.
Yes, I completely forgot about the horizontal line. Then I wouldn't know what they are expecting from writing it in standard form.
I sent my teacher an email and she said it would be one of the following: -2x = 5 -x + 2y = 5 -2y = 5 -5y = 2
Wut...You wrote your problem out wrong breh.
No I didn't?
Is it y = -5/2?
No, it's just y = 5/2
Then maybe it is like this: y = 5/2 y = 0x + 5/2 0x - y = -5/2 I know, it is nonsense. But I don't see any other way.
I declare shenanigans.
The (-1) will still cancel out anyway...
True...
There can't be a negative sign in it. It has to be 2y = 5, if anything.
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