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use half-angle identities to find the exact value of tan 3pi/8
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does it help to know that \(\frac{3\pi}{8}\) is half of \(\frac{3\pi}{4}\) ?
i rather have it solved, please, this one too, tanx(sinx+cotxcosx)=secx
Call t = tan a/2 = tan 3Pi/8. Use trig identity: tan a = 2t/(1 - t^2). tan 3Pi/4 = 2t/(1 - t^2) = -1 (trig table gives tan 3Pi/4 = -1) 2t = -(1 - t^2) = -1 + t^2 --> t^2 - 2t - 1 = 0. Use the formula to solve this quadratic equation. It has 2 real roots: x1 = 1 + V2 and x2 = 1 - V2. Since tan 3Pi/8 is positive (tan 3Pi/4 < 0), then x2 is rejected.
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