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Calculus1 23 Online
OpenStudy (anonymous):

f(x)=[x^3-2x^2] find the values of x that make this function not continuous []->absolute value

OpenStudy (mathmale):

If you're discussing an absolute value function here, write it as y = |x^3 - 2x^2|.

OpenStudy (mathmale):

First: think about what a "not continuous" function would look like. Is there anything about y=|x^3 - 2x^2| that would make you think that the graph is broken? Is there a denominator? Think about this. Look up "continuity." Then decide how to respond to this question.

OpenStudy (anonymous):

the function is continuous everywhere right?

OpenStudy (mathmale):

Because there's no division by zero, that would be my conclusion. Nice work!

OpenStudy (anonymous):

f(x)=x+3/|x^3+3x| this function should not be continuous for the values 0 and -3 right?

OpenStudy (anonymous):

f(x)=x+3/|x^3+3x| this function should not be continuous for the values 0 and -3 right?

OpenStudy (mathmale):

At any x at which the denominator is zero, right. Your answers sound correct! You could check by graphing this function on a graphing calculator.

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