f(x)=[x^3-2x^2] find the values of x that make this function not continuous []->absolute value
If you're discussing an absolute value function here, write it as y = |x^3 - 2x^2|.
First: think about what a "not continuous" function would look like. Is there anything about y=|x^3 - 2x^2| that would make you think that the graph is broken? Is there a denominator? Think about this. Look up "continuity." Then decide how to respond to this question.
the function is continuous everywhere right?
Because there's no division by zero, that would be my conclusion. Nice work!
f(x)=x+3/|x^3+3x| this function should not be continuous for the values 0 and -3 right?
f(x)=x+3/|x^3+3x| this function should not be continuous for the values 0 and -3 right?
At any x at which the denominator is zero, right. Your answers sound correct! You could check by graphing this function on a graphing calculator.
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