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Mathematics 7 Online
OpenStudy (anonymous):

A Doozy of a probability question. This one has my head spinning! A college administration has conducted a study of 169 randomly selected students to determine the relationship between satisfaction with academic advisement and academic success. They obtained the following: Of the 74 students on academic probation, 43 are not satisfied with the advisement; however, only 18 of the students not on academic probation are dissatisfied with advisement. What is the probability that a student selected at random is on academic probation and is not satisfied with advisement?

ganeshie8 (ganeshie8):

probability tree might come in handy

ganeshie8 (ganeshie8):

you need to find : P(not satisfied | academic probation) right ?

OpenStudy (anonymous):

It helps if you draw a 2 way table

OpenStudy (anonymous):

Yes P(not satisfied | academic probation)

ganeshie8 (ganeshie8):

unless the question is asking about "sampling distribution" and finding the pvalues, its a simple proability tree/contingency table problem

ganeshie8 (ganeshie8):

heard of any of them before ?

OpenStudy (anonymous):

|dw:1395890924782:dw|

OpenStudy (anonymous):

Can you fill the table?

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