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Physics 9 Online
OpenStudy (anonymous):

Calculate the diameter of the fifteenth orbit of the hydrogen atom if the diameter of the innermost orbit is 1.06 A

OpenStudy (anonymous):

Well, you should be working from Bohr's model, and Bohr calculated the radius of a hydrogen electron orbital of a given energy level as follows: \[r _{n}=\frac{ n ^{2} ℏ^{2}}{ Zk _{e}e ^{2}m _{e} }\]where n is the energy level; Z is the atomic number, ke is the Coulomb constant, e is the charge of an electron, and me is the electron mass. Now before you leap for the calculator to start plugging in a bunch of numbers consider this: how does orbital radius vary with the energy level? You should see that you can get the answer with a very simple and quick calculation.

OpenStudy (anonymous):

Does that help?

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