If you had 100 milliters of cold water at 25 degrees Celsius and mixed them with 90 grams of hot water at 80 degrees Celsius and you obtained a mixture that reached a final temperature of 40 degrees Celsius, determine the Calorimeter Constant for your thermos.

Question

anonymous · Answer

I know you have to use the equation $$mCDeltaT=-(mCDeltaT+CcDeltaT)$$ I just don't know where to plug in the values.

shrutipande9 · Answer

@AravindG @wolfe8

aravindg · Answer

The thermal content added is the mass * specific heat capacity * temperature change

Q=mc(delta T)

Create the equations and solve.

anonymous · Answer

Uhh. Please talk to me as if I am a special child lol. Cus that went right over my head.

aaronq · Answer

$\underbrace{m*C*(T_f-T_i)}_{hot~water}=−[\underbrace{m*C*(T_f-T_i)}_{cold~water}+\underbrace{C*(T_f-T_i)}_{calorimeter}]$

I guess you have to assume that the calorimeter is at the same initial temp as the cold water.

anonymous · Answer

thank you Aaron