how can i find a point that lies on the line y-6=3(x-5)

Question

whpalmer4 · Answer

Plug in a value for $x$, and solve for the value of $y$.  Then $(x,y)$ is a point on the line.

For example, if you had the equation $$y+3 = 2(x+4)$$and you felt like finding the point that was on the line at $x=13$, you plug in $x=13$ and find the value of $y$ that results:
$$y+3=2(13+4)$$$$y+3=2*17$$$$y+3=34$$$$y+3-3=34-3$$$$y=31$$So $(13,31)$ is a point on my line.

anonymous · Answer

okay ill try :) thanks for helping

whpalmer4 · Answer

What is it that Yoda says? :-)

anonymous · Answer

i filled x in with 10 and i did the math and i got (10,21) for a point on the line

whpalmer4 · Answer

Excellent! https://www.youtube.com/watch?v=BQ4yd2W50No

anonymous · Answer

is there any chance you can help me find a slope of a line?

whpalmer4 · Answer

I suspect I can.

anonymous · Answer

so basically the same layout its y-4=-9(x-8)

anonymous · Answer

im not sure but is the slope -9?

whpalmer4 · Answer

Okay.  This form is called point-slope form:
$$y-y_1 = m(x-x_1)$$where $m$ is the slope, and $(x_1,y_1)$ is a point that the line goes through.

whpalmer4 · Answer

so yes, you are correct.

anonymous · Answer

oh thank you :)

whpalmer4 · Answer

You're welcome!

anonymous · Answer

i also gave you medal :)

whpalmer4 · Answer

Tanks in advance, film at 11...

whpalmer4 · Answer

(of course, it works better if I say that before you do something for me, but...)