Question

HELPPPPP
find the slope of a line perpendicular
-x-3-y=0

Answer 1

First I'd suggest changing the form of the equation into slope intercept form (y=mx+b). Then it'll be easier to work with.

Answer 2

Do u know the property of two perpendicular lines?

Answer 3

Put the equation in the form of y=mx+c

Answer 4

I tried putting it into y = mx + b but I don't know if its right

Answer 5

so a perpendicular line satisfies the condition that it's slope is the negative reciprocal of the initial line's slope.
once you have the initial equation in y=mx+b then you can easily determine the slope of the initial line.
then find the new slope by taking the negative reciprocal of the original slope.

Answer 6

so do I plug in the 3 for b?

Answer 7

0 = -x - 3?

Answer 8

where did the 0 come from?
you're close. you should add y to each side to get y= instead of 0 equals.

Answer 9

y = 0

Answer 10

Just isolate "y" and put every damn thing to the other side of the equation but remember y should be positive

Answer 11

not quite..
so you start with the equation -x-3-y=0
and you want the equation to be in y= form. right now you have negative y on the left side, so the easiest way to get it into y= form is to add y to each side:

now its in y = form so whats the slope?