Question

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Answer 1

A sells an article to B who in turn sells it to C. B looses as much percentage loss as A's percentage profit. If A brought the article at 100 and C at 64 then B buys the article at?

Answer 2

let a sell at x% profit

Answer 3

OK

Answer 4

profit=100*(x/100)=x

Answer 5

b will bought it at =100+x

Answer 6

how profit=100*(x/100)=x

Answer 7

now B sell at loss =profit % of A=x%
loss=(100+x)*(x/100)

Answer 8

2% means 2/100
5% means 5/100
and x% means x/100

Answer 9

yes i got it

Answer 10

now c bought it at
=(100+x)-loss of B

Answer 11

yes

Answer 12

c purchased at =64 = given in Q
loss of B we calculated
64=(100+x)-(100+x)*x/100

Answer 13

multiply both side by 100

Answer 14

so B buys at 160

Answer 15

\[64*100=100*(x+100)-(x+100)*\frac{ x }{ 100 }*100\]

Answer 16

6400=100x+10000-x^2-100x

Answer 17

So x = 60

Answer 18

so B buys at 160

Answer 19

6400=10000-x^2
x^2=10000-6400
x^2=3600
x=60

Answer 20

now can u do it

Answer 21

thank u

Answer 22

wlcme:)