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OpenStudy (anonymous):
First derivative of y= 10^cos3x
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OpenStudy (anonymous):
\[y= 10^{\cos3x}\]
OpenStudy (kainui):
Show your best guess and we'll help you. =)
OpenStudy (anonymous):
my answer was - 30 cos 3x
OpenStudy (anonymous):
it was wrong..
OpenStudy (anonymous):
wonr, its -30sin3x.
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OpenStudy (anonymous):
yep it's wrong
OpenStudy (kainui):
You can rewrite it like this:
\[y=e^{\ln10*\cos3x}\]
I think it makes it easier to think about when it's like this.
OpenStudy (anonymous):
the derivative of
\[a ^{u} = u \prime \times a ^{u} \times lna\]
OpenStudy (anonymous):
@silverxx can u try to solve it ?
OpenStudy (anonymous):
-3 sin3x (10) ?
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OpenStudy (anonymous):
nope
OpenStudy (anonymous):
really have no idea ;(
OpenStudy (kainui):
You need to use the chain rule here.
OpenStudy (anonymous):
listen the derivative of a^u=u′×a^u×lna
u have 10^cos3x
u′=-3sin3x
a^u=10^cos3x
lna=ln10
so the derivative of 10^cos3x=-3sin3x*10^cos3x*ln10
OpenStudy (anonymous):
is it.. cos 3x [ (10) (-3sin3x)]?
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OpenStudy (anonymous):
it's \[-3\sin3x \times10^{\cos3x}\times \ln 10\]
OpenStudy (anonymous):
@silverxx
OpenStudy (anonymous):
got it ?
OpenStudy (anonymous):
woah. tsk. Thank you so much!! again.
OpenStudy (anonymous):
Anytime. :D
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