write the system [ 2y + 7z=-3] as a matrix equation
[-3x - 3y= 3]
[7x - 8z= 3]
A. [2 7] [x] [-3]
[-3 -3] [y] = [3 ]
[0 -8] [z] [3 ]

B. [0 -3 7] [x] [-3]
[2 -3 0] [y]= [3 ]
[7 0 -8] [z] [3 ]

C. [0 2 7] [x] [-3]
[-3 -3 -8] [y]= [3]
[7 0 -8] [z] [3]

D. [-3 7] [x] [-3]
[2 -3] [y]= [3]
[7 -8] [z] [3]

Question

write the system [ 2y + 7z=-3] as a matrix equation 
                               [-3x - 3y=  3]
                                [7x  - 8z=   3]
A. [2    7]   [x]    [-3]
    [-3  -3]   [y] = [3 ]
    [0    -8]  [z]    [3  ]

B. [0  -3  7] [x]   [-3]
    [2   -3 0] [y]= [3 ]
    [7   0 -8] [z]   [3  ]

C.  [0   2    7] [x]    [-3]
     [-3  -3  -8] [y]=  [3]
     [7    0   -8] [z]    [3]

D. [-3  7]  [x]    [-3]
    [2   -3]  [y]=  [3]
    [7   -8]  [z]    [3]

anonymous · Answer

B. 
Just take a look at the pattern we have there...

anonymous · Answer

The coefficients are gonna be in their respective columns. Arrange that, and then you'll see it makes perfect sense! :)

anonymous · Answer

okay how did you do that so i know

anonymous · Answer

oh okay thank you so much

anonymous · Answer

First eqn in the system doesnt have a value for x so, coeff of x there is zero

anonymous · Answer

could you by chance help me with another one

anonymous · Answer

Go through the other eqns, and you see thesame patterns for y and z

anonymous · Answer

I would if I can :)

anonymous · Answer

solve the system using matrices 
{ x+2y=-1
{-x-3y=-2

A. [-7]
    [3]

B. [3]
    [-7]

C. [7]
     [-3]

D. no solution

anonymous · Answer

attachment

anonymous · Answer

okay that helped so much thanks for the help :)

anonymous · Answer

Uw :)